A) zero
B) \[2\pi {{r}^{2}}E\]
C) \[\pi {{r}^{2}}E\]
D) \[(\pi {{r}^{2}}+\pi {{l}^{2}})\,E\]
Correct Answer: A
Solution :
Let us take a small area \[\Delta S\] on the cylindrical surface. The normal to this area will be perpendicular to the axis of the cylinder and electric field is parallel to axis of cylinder. So, flux \[\Delta \,\phi =\vec{E}\,.\,\Delta \,\vec{S}\] \[=E\,\Delta \,S\cos {{90}^{o}}\] = 0 Summing over the entire surface, the total flux from the surface of cylinder is zero.You need to login to perform this action.
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