A) 2,2-dimethyl propane
B) pentane
C) 2-methyl butane
D) 2,2-dimethyl butane
Correct Answer: D
Solution :
2, 2-dimethyl butane is 6-carbon hydrocarbon\[({{C}_{6}}{{H}_{14}})\]. \[C{{H}_{3}}-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,}}\,-C{{H}_{2}}-C{{H}_{3}}\] Rest all are the chain isomers of pentane.\[({{C}_{5}}{{H}_{12}})\] \[\underset{\begin{smallmatrix} 2,\text{ }2-dimethyl\text{ }propane \\ (neo-pentane) \end{smallmatrix}}{\mathop{{{H}_{3}}C-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,}}\,-C{{H}_{3}},}}\,\] \[\underset{\begin{smallmatrix} 2-methylbutane \\ (iso-pentane) \end{smallmatrix}}{\mathop{{{H}_{3}}C-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{2}}}}\,-C{{H}_{3}}\] \[\underset{w-pentane}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}}}\,\]
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