A) \[\sec \,{{h}^{2}}x\]
B) \[\cos ec\,{{h}^{2}}x\]
C) \[\sec \,\,{{h}^{2}}x\]
D) \[-\cos ec\,{{h}^{2}}x\]
Correct Answer: D
Solution :
\[y=\frac{({{e}^{x}}+{{e}^{-x}})}{({{e}^{x}}-{{e}^{-x}})/2}=\frac{\cosh x}{\sinh x}\]\[y=\cot \,h\,x\] On differentiating with respect to \[x\], we get \[\frac{dy}{dx}=-\cos ec{{h}^{2}}x\]You need to login to perform this action.
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