CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2005

  • question_answer
    The electric flux for Gaussian surface A that enclose the charged particles in free space is (given \[{{q}_{1}}=14nC,{{q}_{2}}=78.85nC,{{q}_{3}}=-56nC\])

    A)  \[{{10}^{3}}N{{m}^{2}}{{C}^{-1}}\]

    B)  \[{{10}^{3}}C{{N}^{-1}}{{m}^{-2}}\]

    C)                  \[6.32\times {{10}^{3}}N{{m}^{2}}{{C}^{-1}}\]

    D)  \[6.32\times {{10}^{3}}C{{N}^{-1}}{{m}^{-2}}\]

    Correct Answer: A

    Solution :

    Electric flux \[=\frac{q}{{{\varepsilon }_{0}}}\]                 \[=\frac{(-14+78.85-56)\times {{10}^{-9}}}{8.85\times {{10}^{-12}}}\]                 \[=\frac{8.85\times {{10}^{-9}}}{8.85\times {{10}^{-12}}}=1000\,N{{m}^{2}}{{C}^{-1}}\]


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