A) 0
B) - 1
C) 1/2
D) 1
Correct Answer: D
Solution :
\[\cos \,({{270}^{o}}+\theta )\,\cos \,({{90}^{o}}-\theta )\] \[-\sin \,({{270}^{o}}-\theta )\,\cos \theta \] \[=\sin \,\theta \,.\,\,\sin \theta +\cos \theta \,.\,\cos \theta \] \[={{\sin }^{2}}\theta +{{\cos }^{2}}\theta =1\]You need to login to perform this action.
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