CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2005

  • question_answer
    Mean life of a radioactive sample is 100 seconds. Then its half-life (in minutes) is:

    A)  0.693                   

    B)  1

    C)  \[{{10}^{-4}}\]                                 

    D)  1.155

    Correct Answer: D

    Solution :

    Half life \[T/2=\frac{T}{1.44}=\frac{100}{1.44}\sec \]                                 \[=69.44\,\sec \]                                 \[=\frac{69.44}{60}\approx 1.155\,\min \]


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