A) 11.875
B) 26.31
C) 118.75
D) none of these
Correct Answer: C
Solution :
\[{{R}_{2}}\,,\,\,{{R}_{3}}\] and \[{{R}_{4}}\] are m parallel order, so their equivalent resistance \[\frac{1}{R}=\frac{1}{{{R}_{2}}}+\frac{1}{{{R}_{3}}}+\frac{1}{{{R}_{4}}}\] \[=\frac{1}{50}+\frac{1}{50}+\frac{1}{75}=\frac{30+30+20}{1500}\] \[=\frac{80}{1500}=\frac{4}{75}\] \[\therefore \] \[R=\frac{75}{4}\,\,\Omega \] \[R={{R}_{1}}+R\] \[=100+\frac{75}{4}\] \[=\frac{475}{4}\Omega \] \[118.75\,\Omega \]You need to login to perform this action.
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