A) \[\frac{1}{2}PV\]
B) PV
C) 2 PV
D) 4 PV
Correct Answer: B
Solution :
Work done during the cycle = area enclosed by P-V graph = area of \[\,ABCD\] \[=\,AD\times CD\] \[=(2V-V)\times (2\,P-P)\] \[=PV\]You need to login to perform this action.
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