A) \[1<2<3\]
B) \[2<3<1\]
C) \[3<2<1\]
D) \[3<1<2\]
Correct Answer: C
Solution :
From the figure. \[{{T}_{1}}\cos {{30}^{o}}={{T}_{2}}\cos {{30}^{o}}\] \[\therefore \] \[{{T}_{1}}={{T}_{2}}=T\] (Let) Again \[{{T}_{1}}\sin {{30}^{o}}+{{T}_{2}}\sin {{30}^{o}}=10\] \[2T\sin {{30}^{o}}=10\] \[2T.\frac{1}{2}=10\,\,\,\,\Rightarrow \,\,\,\,T=10N\] \[\therefore \] Tension m section DC and BF are 10 N and 10 NYou need to login to perform this action.
You will be redirected in
3 sec