A) \[{{n}_{1}}=8,{{n}_{2}}=1\]
B) \[{{n}_{1}}=4,{{n}_{2}}=2\]
C) \[{{n}_{1}}=2,{{n}_{2}}=4\]
D) \[{{n}_{1}}=1,{{n}_{2}}=8\]
Correct Answer: B
Solution :
In a hydrogen atom the time period is given by \[T\propto {{n}^{3}}\] \[\frac{{{T}_{1}}}{{{T}_{2}}}={{\left( \frac{{{n}_{1}}}{{{n}_{2}}} \right)}^{3}}\Rightarrow \frac{8}{1}={{\left( \frac{{{n}_{1}}}{{{n}_{2}}} \right)}^{3}}\] \[\therefore \] \[\frac{{{n}_{1}}}{{{n}_{2}}}=\frac{2}{1}\] Thus, \[{{n}_{1}}=4\] and \[{{n}_{2}}=2\]You need to login to perform this action.
You will be redirected in
3 sec