A) \[{{375}^{o}}C\]
B) 375K
C) 273 K
D) \[{{102}^{o}}C\]
Correct Answer: B
Solution :
\[\Delta S=16\,J\,\,mo{{l}^{-1}}{{K}^{-1}},\Delta {{H}_{\upsilon }}=6\,kJ\,mo{{l}^{-1}}\] \[{{T}_{b.p.}}=\frac{\Delta {{H}_{vapour}}}{\Delta {{S}_{vapour}}}=\frac{6\times 1000}{16}=375\,K\]You need to login to perform this action.
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