A) \[a+b+ab\]
B) \[{{a}^{2}}+{{b}^{2}}\]
C) \[ab+1\]
D) \[2a+3b\]
Correct Answer: A
Solution :
Let us assume \[a*b=a+b+ab\] Now, \[a*(b*c)=a*(b+c+bc)\] \[=a+b+c+ab+ac+abc\] \[=a+b+ab+c+ac+abc\] \[=(a*b)*c\] \[\therefore \] It is associative Now \[a\,\,*\,\,b=a+b+ab\] \[=b+a+ba\] \[=b*a\] Also, it is commutative. \[\therefore \] Our assuming operation is true.You need to login to perform this action.
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