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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2006

  • question_answer
    If \[y=1+\frac{1}{x}+\frac{1}{{{x}^{2}}}+\frac{1}{{{x}^{3}}}+.....\] to \[\infty \] with \[|x|>1\], then \[\frac{dy}{dx}\] is :

    A)  \[\frac{{{x}^{2}}}{{{y}^{2}}}\]                                    

    B)  \[{{x}^{2}}{{y}^{2}}\]

    C)  \[\frac{{{y}^{2}}}{{{x}^{2}}}\]                                    

    D)  \[\frac{-{{y}^{2}}}{{{x}^{2}}}\]

    Correct Answer: D

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