A) NOT
B) AND
C) OR
D) NAND
Correct Answer: B
Solution :
The output of the circuit is, \[y=\overline{\overline{A}+\overline{B}}\] \[y=\overline{\overline{A}}\,.\,\overline{\overline{B}}\] \[=\overline{A}\,.\,B\] (\[\because \,\overline{A}=A\] and \[\overline{B}=B\]) which is the output of an AND gate.You need to login to perform this action.
You will be redirected in
3 sec