A) zero to 4 - 5
B) +1 to +5
C) zero to -3
D) +2 to +5
Correct Answer: A
Solution :
Bromine has zero oxidation state because it is in free state \[\overset{0}{\mathop{B{{r}_{2}}}}\,\xrightarrow{{}}BrO_{3}^{-}\] \[\overset{0}{\mathop{Br}}\,\overset{-2}{\mathop{O_{3}^{-}}}\,\] \[x+(-2\times 3)=-1\] \[x+(-6)=-1\] \[x=+6-1\] \[=+5\] So, oxidation number changes from 0 to +5.You need to login to perform this action.
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