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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2006

  • question_answer
    The decomposition of a certain mass of \[CaC{{O}_{3}}\] gave \[11.2\text{ }d{{m}^{3}}\] of \[C{{O}_{2}}\] gas at STR The mass of KOH required to completely neutralise the gas is :

    A)  56 g                                      

    B)  28 g

    C)  42 g                                      

    D)  20 g

    Correct Answer: B

    Solution :

    Weight of \[11.2\text{ }d{{m}^{3}}\] of \[C{{O}_{2}}\] gas at STP = 44/2                                                                                 = 22g. \[\underset{56\,g}{\mathop{KOH}}\,+\underset{44\,g}{\mathop{C{{O}_{2}}}}\,\xrightarrow{{}}KHC{{O}_{3}}\] KOH required for complete neutralization requires of 22 g of \[C{{O}_{2}}\] is \[=\frac{56}{44}\times 22=28\,g\]


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