A) \[4\]
B) \[8\]
C) \[10\]
D) \[12\]
Correct Answer: D
Solution :
Given, ellipse is \[\frac{{{x}^{2}}}{36}+\frac{{{y}^{2}}}{16}=1\] Here, \[{{a}^{2}}=36,\] \[{{b}^{2}}=16\] Since, \[a>b,\] so the sum of the focal distance of any point P on the ellipse is \[PS+PS'=2a\] \[\Rightarrow \] \[PS+PS'=2\times 6\] \[\Rightarrow \] \[PS+PS'=12\]You need to login to perform this action.
You will be redirected in
3 sec