A) \[{{x}^{2}}+{{y}^{2}}\pm 10x-6y+9=0\]
B) \[{{x}^{2}}+{{y}^{2}}\pm 6x-10y+9=0\]
C) \[{{x}^{2}}+{{y}^{2}}-8x\pm 10y+9=0\]
D) \[{{x}^{2}}+{{y}^{2}}+10x\pm 6y+9=0\]
Correct Answer: A
Solution :
Given, equation of circle touch the y-axis at \[(0,3)\]. So, from figure \[r=\sqrt{{{3}^{2}}+{{4}^{2}}}=5\] The point \[(0,3)\] and radius 5 satisfies the equation \[{{x}^{2}}+{{y}^{2}}\pm 10x-6y+9=0.\] Hence, it is the required equation of circle;You need to login to perform this action.
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