A) \[16\text{ }sq\text{ }unit\]
B) \[32\text{ }sq\text{ }unit\]
C) \[\frac{32}{3}\text{ }sq\text{ }unit~~\]
D) \[\frac{16}{3}sq\text{ }unit\]
Correct Answer: C
Solution :
Given, curve \[x=4-{{y}^{2}}\] and y-axis. The formed area is ABCOA \[=2\times \]area of ABOA \[=2\times \int_{0}^{4}{\sqrt{4-x}}dx\] \[=2\left[ \frac{{{(4-x)}^{3/2}}}{3/2} \right]_{0}^{4}\] \[=2\left[ -\frac{2}{3}\times 0+\frac{2}{3}{{(4)}^{3/2}} \right]\] \[=\frac{4}{3}\times 8=\frac{32}{3}sq\,unit\]You need to login to perform this action.
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