CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2007

  • question_answer
    The de-Broglie wavelength of a proton (charge \[=1.6\times {{10}^{-19}}C\], mass \[=1.6\times {{10}^{-27}}kg\]) accelerated through a potential difference of 1 kV is

    A)  \[600\,\overset{o}{\mathop{A}}\,\]                      

    B)  \[0.9~{{10}^{-12}}m\]

    C)  \[7\,\overset{o}{\mathop{A}}\,\]                          

    D)  0.9 nm

    Correct Answer: B

    Solution :

    According to de-Broglie hypothesis                 \[\lambda =\frac{h}{p}\]                 \[=\frac{h}{\sqrt{2\,mE}}=\frac{h}{\sqrt{2\,mqV}}\] \[\therefore \]    \[\lambda =\frac{6.6\times {{10}^{-34}}}{\sqrt{2\times (1.6\times {{10}^{-27}})(1.6\times {{10}^{-19}})\times 1000}}\]                 \[=\frac{6.6\times {{10}^{-34}}}{7.16\times {{10}^{-22}}}\]                 \[=0.9\times {{10}^{-12}}m\]


You need to login to perform this action.
You will be redirected in 3 sec spinner