A | B | Y |
0 | 0 | 1 |
0 | 1 | 1 |
1 | 0 | 1 |
1 | 1 | 0 |
A) NOR
B) AND
C) XOR
D) NAND
Correct Answer: D
Solution :
The output Y is a combination of AND + NOT gate. Hence, the truth table is for NAND gate.You need to login to perform this action.
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