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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2007

  • question_answer
    In a reverse biased diode when the applied voltage changes by 1 V, the current is found to change by \[0.5\,\mu A\] The reverse bias resistance of the diode is

    A)  \[2\times {{10}^{5}}\Omega \]                 

    B)  \[2\times {{10}^{6}}\Omega \]

    C)  \[200\,\Omega \]                           

    D)  \[2\,\Omega \]

    Correct Answer: B

    Solution :

    Reverse resistance                 \[=\frac{\Delta V}{\Delta \,I}=\frac{1}{0.5\times {{10}^{-6}}}\]                  \[=2\times {{10}^{6}}\Omega \]


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