A) 30 kJ
B) 10 kJ
C) 4 kJ
D) 1 kJ
Correct Answer: B
Solution :
Efficiency \[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}\] \[=1-\frac{(273+27)}{(273+127)}\] \[=1-\frac{300}{400}\] \[=\frac{1}{4}\] \[\eta =\frac{Work\text{ }done}{Heat\text{ }supplied}\] \[\frac{1}{4}=\frac{W}{40}\] \[\Rightarrow \] \[W=10\,kJ\]You need to login to perform this action.
You will be redirected in
3 sec