A) \[4400\overset{o}{\mathop{A}}\,\]
B) \[4100\overset{o}{\mathop{A}}\,\]
C) \[4642.8\overset{o}{\mathop{A}}\,\]
D) \[9100\overset{o}{\mathop{A}}\,\]
Correct Answer: C
Solution :
\[x=\frac{(2\,n+1)\,\lambda D}{2\,a}\] For red light \[x=\frac{(4+1)\,D}{2\,a}\times 6500\] For unknown wavelength of light, \[x=\frac{(6+1)\,D}{2\,a}\times \lambda \] Accordingly \[\therefore \] \[5\times 6500=7\times \lambda \] \[\Rightarrow \] \[\lambda =\frac{5}{7}\times 6500\] \[=\text{ }4642.8\text{ }\overset{o}{\mathop{A}}\,\]You need to login to perform this action.
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