A) \[50\text{ }m{{s}^{-1}}\]
B) \[5\text{ }m{{s}^{-1}}\]
C) \[0.05\text{ }m{{s}^{-1}}\]
D) \[0.5\text{ }m{{s}^{-1}}\]
Correct Answer: B
Solution :
According to equation of continuity, \[av=\] constant \[\therefore \] For tube, \[(8\times {{10}^{-4}})\times \left( \frac{0.15}{60} \right)={{a}_{1}}{{v}_{1}}\] For holes, \[(40\times {{10}^{-8}})\times v={{a}_{2}}{{v}_{2}}\] \[\therefore \] \[{{a}_{2}}{{v}_{2}}={{a}_{1}}{{v}_{1}}\] \[\therefore \] \[40\times {{10}^{-8}}\times v=\frac{8\times {{10}^{-4}}\times 0.15}{60}\] \[\Rightarrow \] \[v=\frac{8\times {{10}^{-4}}\times 0.15}{40\times {{10}^{-8}}\times 60}\] \[=5\text{ }m/s\]You need to login to perform this action.
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