A) \[100\pi \,sq\,m\]
B) \[5\,sq\,cm\]
C) \[25\,sq\,cm\]
D) \[\frac{100\pi }{3}\,sq\,cm\]
Correct Answer: A
Solution :
In \[\Delta ABC,\]\[\angle A={{30}^{o}}\] \[BC=10cm\] O is the centre of circle \[\therefore \] \[\angle BOC={{60}^{o}}\]and OB and OC are the radius \[\therefore \] \[\angle OBC=\angle OCB={{60}^{o}}\] \[\Rightarrow \]\[\Delta OBC\] OBC is an equilateral triangle \[\therefore \] S Radius of circle is \[OB=OC=BC=10\text{ }cm\] Now, area of the circum circle is \[\pi {{r}^{2}}\] \[=\pi {{(10)}^{2}}=100\pi \,\,sq\,cm\]You need to login to perform this action.
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