A) 1.33
B) 1.414
C) 1.5
D) 1.732
Correct Answer: B
Solution :
Refractive index, \[\mu =\frac{1}{\sin \,C'}\] where C is the critical angle. Here, \[C={{45}^{o}}\] (as shown) \[\therefore \] \[\mu =\frac{1}{\sin \,{{45}^{o}}}\] or \[\mu =\sqrt{2}\] or \[\mu =1.414\]You need to login to perform this action.
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