A) 95
B) 45
C) 60
D) 30
Correct Answer: A
Solution :
\[\underset{190}{\mathop{SnC{{l}_{2}}}}\,+\underset{71}{\mathop{C{{l}_{2}}}}\,\xrightarrow{{}}SnC{{l}_{4}}\] \[\frac{190}{{{E}_{1}}}=\frac{71}{35.5}\] \[{{E}_{1}}\,\,\,\,=\,\,\,\,95\]You need to login to perform this action.
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