A) \[-6\]
B) \[-9\]
C) \[6\]
D) \[-3\]
Correct Answer: D
Solution :
Given, \[{{x}^{3}}-6x+9=0\] \[\Rightarrow \] \[(x+3)({{x}^{2}}-3x+3)=0\] \[\Rightarrow \] \[x=-3\] or \[{{x}^{2}}-3x+3=0\] Now, Discriminant, \[D=\sqrt{9-4\times 3}\] \[=\sqrt{-3}\] imaginary Hence, real roots of the given equation is \[x=-3\]You need to login to perform this action.
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