A) \[x+y=4\]
B) \[x+y=8\]
C) \[x+y=1\]
D) \[x+y=2\]
Correct Answer: D
Solution :
Let the coordinate of mid point of AB is \[({{x}_{1}},{{y}_{1}})\]. \[\therefore \] \[{{x}_{1}}=\frac{a+0}{2},{{y}_{1}}=\frac{0+b}{2}\] \[\Rightarrow \] \[a=2{{x}_{1}},b=2{{y}_{1}}\] Given, \[a+b=4\] \[\therefore \] \[2{{x}_{1}}+2{{y}_{1}}=4\] \[\Rightarrow \] \[{{x}_{1}}+{{y}_{1}}=2\] Hence, the locus of the mid point is \[x+y=2\]You need to login to perform this action.
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