A) \[4\]
B) \[3!\]
C) \[5\]
D) \[7\]
Correct Answer: B
Solution :
As we know the last two digits of 10! and above factorials will be zero-zero. \[\therefore \] \[1!+4!+7!+10!+12!+13!+15!+16!+17!\] \[=1+24+5040+10!+12!+13!\] \[+15!+16!+17!\] \[=5065+10!+12!+13!+15!+16!+17!\] In this series, the digit in the ten place is 6 which is divisible by \[3!\].You need to login to perform this action.
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