A) \[1:3\]
B) \[3:1\]
C) \[1:2\]
D) \[2:1\]
Correct Answer: B
Solution :
As the current and the other factors are same for both the galvanometers \[N\propto \tan \theta \] \[\frac{{{N}_{1}}}{{{N}_{2}}}=\frac{\tan {{60}^{o}}}{\tan {{30}^{o}}}\] \[=\frac{\sqrt{3}}{1/\sqrt{3}}\] \[\Rightarrow \] \[\frac{{{N}_{1}}}{{{N}_{2}}}=3\]You need to login to perform this action.
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