CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2008

  • question_answer
    The ratio of the nuclear radii of elements with mass numbers 216 and 125 is

    A)  \[216:125\]      

    B)  \[\sqrt{216}:\sqrt{125}\]

    C)  \[6:5\]                                 

    D)  None of these

    Correct Answer: C

    Solution :

    Nuclear radius is proportional to \[{{A}^{1/3}}\], where A is the mass number of nucleus.                 \[R={{R}_{0}}{{A}^{1/3}}\] where   \[{{R}_{0}}=1.2\,fm\]                 \[\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{{{R}_{0}}{{(216)}^{1/3}}}{{{R}_{0}}{{(125)}^{1/3}}}=\frac{6}{5}\]


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