A) \[[{{M}^{-1}}{{L}^{2}}{{T}^{-2}}]\]
B) \[[{{M}^{0}}{{L}^{0}}{{T}^{0}}]\]
C) \[[{{M}^{-1}}{{L}^{3}}{{T}^{-2}}]\]
D) \[[{{M}^{-1}}{{L}^{3}}{{T}^{-1}}]\]
Correct Answer: C
Solution :
\[F=\frac{G{{M}_{1}}{{M}_{2}}}{{{R}^{2}}}\] \[\Rightarrow \] \[G=\frac{F{{R}^{2}}}{{{M}_{1}}{{M}_{2}}}\] \[\therefore \] \[[G]=\frac{[ML{{T}^{-2}}]\,[{{L}^{2}}]}{[{{M}^{2}}]}=[{{M}^{-1}}{{L}^{3}}{{T}^{-2}}]\]
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