A) \[5\]
B) \[15\]
C) \[16\]
D) \[17\]
Correct Answer: D
Solution :
Given, \[{{p}^{2}}-2{{q}^{2}}=1\] ...(i) Since, p and q are prime numbers. Let \[p=3\]and \[q=2\] \[\therefore \]From Eq.(i), \[{{(3)}^{2}}-2{{(2)}^{2}}=1\] \[\Rightarrow \] \[9-8=1\] \[\Rightarrow \] \[1=1\] Therefore, our assumption is true. Now, \[{{p}^{2}}+2{{q}^{2}}={{(3)}^{2}}+2{{(2)}^{2}}=9+8=17\]You need to login to perform this action.
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