A) 20 kg - wt
B) 10 kg - wt
C) \[10\sqrt{3}\,kgwt\]
D) \[20\sqrt{3}\,kg-wt\]
Correct Answer: A
Solution :
The situation is shown in figure At an angle of \[{{60}^{o}}\], \[T\,\cos \theta =mg\] \[T=\frac{mg}{\cos \theta }=\frac{10\,g}{\cos \,{{60}^{o}}}\] \[=\frac{10}{1/2}kg-wt\]. = 20 kg-wtYou need to login to perform this action.
You will be redirected in
3 sec