A) \[1\]
B) \[2\]
C) \[\infty \]
D) \[0\]
Correct Answer: B
Solution :
Given, \[y=4x+c\] and \[\frac{{{x}^{2}}}{4}+{{y}^{2}}=1\] Condition for tangency, \[{{c}^{2}}={{a}^{2}}{{m}^{2}}+{{b}^{2}}\] \[\therefore \] \[{{c}^{2}}=4{{(4)}^{2}}+{{1}^{2}}\] \[\Rightarrow \] \[{{c}^{2}}=65\] \[\Rightarrow \] \[c=\pm \sqrt{65}\] Hence, for two values of c, the line touches the curve.You need to login to perform this action.
You will be redirected in
3 sec