A) 1.93 A
B) 9.65 A
C) 19.3 A
D) 0.965 A
Correct Answer: B
Solution :
No. of moles of \[{{H}_{2}}=\frac{1.12}{22400}\] No. of equivalence of hydrogen \[=\frac{1.12}{22400}={{10}^{-4}}\] No. of Faradays required \[={{10}^{-4}}\] \[\therefore \] Current to be passed in one second \[=\text{ }96500\times {{10}^{-4}}\] \[=9.65\text{ }A\]You need to login to perform this action.
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