A) \[A{{B}_{2}}\]
B) \[{{A}_{3}}B\]
C) \[AB\]
D) \[A{{B}_{3}}\]
Correct Answer: D
Solution :
A occupies comers, thus number of A atoms per unit cell \[=8\times \frac{1}{8}=1\] B occupies face centres, thus number of B atoms per unit cell \[=6\times \frac{1}{8}=3\] \[\therefore \] The empirical formula of the compound is\[A{{B}_{3}}\].You need to login to perform this action.
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