A) \[10\text{ }\Omega \]
B) \[20\text{ }\Omega \]
C) \[8\text{ }\Omega \]
D) \[5\text{ }\Omega \]
Correct Answer: A
Solution :
Given, galvanometer resistance \[G=240\text{ }\Omega \] Shunt resistance S = ? \[{{I}_{G}}=\frac{4}{100}I\] From figure voltage through the circuit. \[(I-{{I}_{G}})S={{I}_{G}}G\] or \[\left( 1-\frac{4I}{100} \right)S=\frac{4I}{100}\times 240\] or \[S=\frac{4\times 240}{96}=10\,\Omega \]You need to login to perform this action.
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