A) 4000 Pa
B) 2000 Pa
C) 1000 Pa
D) 500 Pa
Correct Answer: D
Solution :
According to equation of continuity \[{{A}_{1}}{{v}_{1}}={{A}_{2}}{{v}_{2}}\] \[10\times 1=5\times {{v}_{2}}\] \[{{v}_{2}}=2\,m/s\] \[\frac{{{p}_{1}}}{\rho }+\frac{v_{1}^{2}}{2}=\frac{{{p}_{2}}}{\rho }+\frac{v_{2}^{2}}{2}\] \[=\frac{2000}{1000}+\frac{{{1}^{2}}}{2}=\frac{{{p}_{2}}}{1000}+\frac{{{2}^{2}}}{2}\] \[\Rightarrow \] \[{{p}_{2}}=500\,Pa\]You need to login to perform this action.
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