A) 2.292 kJ
B) 1.292kJ
C) 0.292 kJ
D) 3.392 kJ
Correct Answer: A
Solution :
\[HCl\,\,\,\,\,\,\,+\,\,\,\,\,\,\,NaOH\to NaCl+\,\,\,\,{{H}_{2}}O\]Initial moles | \[\frac{200\times 0.2}{1000}\] | 0 | 0 |
= 0.05 | = 0.04 | ||
Final moles | |||
0.05 - 0.04 = 0.01 | 0 | 0.04 | 0.04 |
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