A) nucleophilic attack, transfer of \[{{H}^{-}}\]and transfer of \[{{H}^{+}}\]
B) transfer of \[{{H}^{-}}\], transfer of \[{{H}^{+}}\] and nucleophilic attack
C) transfer if \[{{H}^{+}}\] nucleophilic attack and transfer of \[{{H}^{-}}\]
D) electrophilic attack by \[O{{H}^{-}}\], transfer of\[{{H}^{+}}\] and transfer of \[{{H}^{-}}\]
Correct Answer: A
Solution :
The Cannizaro reaction is as \[HCHO+HCHO\xrightarrow{KOH\,\,(con.)}\underset{methyl\text{ }alcohol}{\mathop{C{{H}_{3}}OH}}\,\] \[+\text{ }\underset{acetic\text{ }acid}{\mathop{HCOO{{K}^{+}}}}\,\] The mechanism of Cannizaro reaction is as Step Ist: Attack of nucleophile \[O{{H}^{-}}\] to the carbonyl carbonYou need to login to perform this action.
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