A) \[156\]
B) \[32\]
C) \[28\]
D) \[56\]
Correct Answer: C
Solution :
We know that, \[a\equiv b(\bmod x)=\frac{(a-b)}{x}\] Given, \[21\equiv 385(\bmod x)=\frac{(21-385)}{x}\] \[=-\frac{364}{x}\] ….(i) and \[587\equiv 167(\bmod x)\] \[=\frac{(587-167)}{x}=\frac{420}{x}\] …..(ii) Now, the greatest value of ‘x’ satisfying Eq. (i) and Eq. (ii) \[=\max [LCM\,of\,(364,\,420)]\] \[\Rightarrow \] \[x=\max \,(13,\,15,\,28)\] \[\Rightarrow \] \[x=28\]You need to login to perform this action.
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