A) For an isochoric process \[=\Delta E=-q\]
B) For an adiabatic process \[=\Delta E=-w\]
C) For an isothermal process \[=q=+w\]
D) For a cyclic process \[q=-w\]
Correct Answer: D
Solution :
First law of Thermodynamics is \[\Delta E=Q+W\] For isochoric process, \[\Delta V=0\] \[w=p\Delta V=0\] \[\therefore \] \[\Delta E=Q\] For adiabatic process, \[Q=0\] \[\Delta E=W\] For isothermal process, \[\Delta T=0\] and \[\Delta E=0\] \[Q=-W\] For cyclic process, state functions like \[\Delta E=0\] \[Q=-W\]
You need to login to perform this action.
You will be redirected in
3 sec
