CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2010

  • question_answer
    A buffer solution contains 0.1 mole of sodium acetate in \[1000\,\,c{{m}^{3}}\] of 0.1 M acetic acid. To the above buffer solution, 0.1 mole of sodium acetate is further added and dissolved. The pH of the resulting buffer is equal to

    A) \[p{{K}_{a}}-\log \,2\]                   

    B) \[p{{K}_{a}}\]

    C) \[p{{K}_{a}}+\,2\]                           

    D) \[p{{K}_{a}}+\log \,2\]

    Correct Answer: D

    Solution :

    Initially \[[C{{H}_{3}}COONa]=0.1\,\,mol\]                 \[[C{{H}_{2}}COOH]=0.1\,\,mol\] when \[0.1\,\,mol\,\,C{{H}_{3}}COONa\] is added.                 \[[C{{H}_{3}}COONa]=0.1+0.1=0.2\,mol\]                                 \[pH=p{{K}_{a}}+\log \frac{[salt]}{[acid]}\]                                 \[=p{{K}_{a}}+\log \frac{0.2}{0.1}\]                                 \[=p{{K}_{a}}+\log \,\,2\]            


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