| (1) The equivalent resistance of the network between points A and B is independent of value of G. |
| (2) The equivalent resistance of the network between points A and B is \[\frac{4}{3}R\] |
| (3) The current through G is zero. |
A) (1) alone
B) (2) alone
C) (2) and (3)
D) (1), (2) and (3)
Correct Answer: D
Solution :
\[{{R}_{eff}}=\frac{(P+Q)\,(R+S)}{(P+Q+R+S)}\] \[{{R}_{eff}}=\frac{4}{3}R\]
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