A) 30
B) 35
C) 46.67
D) 20.8
Correct Answer: B
Solution :
Percentage of nitrogen \[=\frac{1.4\times N\text{ }of\,acid\times Vol.\text{ }used\text{ }with\text{ }N{{H}_{3}}}{Weight\text{ }of\text{ }organic\text{ }compound}\] \[=\frac{1.4\times 1\times 30}{1.2}\] \[=35\]You need to login to perform this action.
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