A) \[-4\]
B) 2
C) 3
D) 4
Correct Answer: D
Solution :
Given, let \[A=2i+3j+0k\] \[B=i+j+k\] \[C=\lambda i+4j+2k\] If A, B, C are the coterminous edges of a parallelepiped then its volume is \[=(A\times B).C\] \[=\{(2i+3j+0k)\times (i+j+k)\}\] \[(\lambda \,i+4j+2k)\] \[=(3\,i-2\,j-k).(\lambda \,i+4\,j+2k)\] \[=3\lambda -8-2\] \[=3\lambda -10\] Given volume =2 \[\Rightarrow \] \[3\lambda -10=2\] \[\Rightarrow \] \[3\lambda =12\] \[\Rightarrow \] \[\lambda =4\]You need to login to perform this action.
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