A) \[\frac{5}{2}\]
B) 5
C) 4
D) 1
Correct Answer: B
Solution :
\[\int_{0}^{4}{|x-1|dx=\int_{0}^{1}{-(x-1)dx+\int_{1}^{4}{(x-1)dx}}}\] \[=-\left[ \frac{{{x}^{2}}}{2}-x \right]_{0}^{1}+\left[ \frac{{{x}^{2}}}{2}-x \right]_{1}^{4}\] \[=-[1/2-1]+[8-4-1/2+1]\] \[=-(-1/2)+(4+1/2)\] \[=1/2+9/2\] \[=5\]You need to login to perform this action.
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